Last Stone Weight
Easy
Heap / Priority Queue
NeetCode 150
You are given an array of integers stones where stones[i] is the weight of the ith stone. We are playing a game with the stones. On each turn, we choose the heaviest two stones and smash them together. Suppose the heaviest two stones have weights x and y with x <= y. The result of this smash is: - If x == y, both stones are destroyed, and - If x != y, the stone of weight x is destroyed, and the stone of weight y has new weight y - x. At the end of the game, there is at most one stone left. Return the weight of the last remaining stone. If there are no stones left, return 0.

Constraints:

  • 1 <= stones.length <= 30
  • 1 <= stones[i] <= 1000